1. The maximum factor of a number is 56, the factor of this number is (). Decompose it into prime factor (). 6, decompose 570 into prime factor () 2. The total edge length of a cube is 48CM, its edge length is () cm, its bottom area is () square cm, its surface area is () square cm, and its volume is () cubic cm 3. In order to make a rectangular downpipe, the pipe orifice is a square with a side length of 15cm and a pipe length of 120cm. How many square centimeters of iron sheet is needed? 4. A rectangular vase with a square bottom, if the side of it is just a cube with a side length of 36cm, what is the volume of the vase? 5. Divide by 2, 5, 3, the remainder is 1, the smallest number is () 6. The cuboid is 6cm in length, 4cm in width and 2cm in height. The total length of its edges is () cm. The largest area of the six sides is () square centimeter, the surface area is () square centimeter, and the volume is () cubic centimeter 7. Saw a cube into two cuboids, its surface area increased by 6 square centimeters, then the surface area of the original cube is () square centimeters 8. A cuboid wardrobe, 1.5m long, 1m wide, 2m wide, is painted on its top, front, left and right sides. How many square meters is the painting area at least? 9. A classroom is 10m in length, 6m in width, 4m in height, with an area of 19.6 square meters of doors and windows. To paint the four walls and ceiling of the classroom, if 0.25 kg of paint is used per square meter, how many kg of paint are needed? 3. Questions 4, 8 and 9 need a process. Just give me an answer to the other questions. My sister won't ask me. I'm too lazy to read them,

1. The maximum factor of a number is 56, and there are (8) factors of this number. Decompose it into prime factors (I learned it in Grade 6, and I have forgotten about it). 6. Decompose 570 into prime factors (·)
2. The total edge length of a cube is 48 cm, its edge length is (4) cm, its bottom area is (16) square cm, its surface area is (96) square cm, and its volume is (64) cubic cm
3. In order to make a rectangular downpipe, the pipe orifice is a square with a side length of 15cm and a pipe length of 120cm. How many square centimeters of iron sheet is needed?
Iron sheet 15 & # 178; x2 + 15x120x4 = 450 + 7200 = 7650 (CM & # 178;)
4. A rectangular vase with a square bottom, if the side of it is just a cube with a side length of 36cm, what is the volume of the vase?
Root 36 = 6 Oh, or just 6 & # 178; = 36 Oh, I forgot how to do it. This is the topic of primary school~
I'm sorry. Even if I'm here, my dad pushed me to sleep··

Decomposition quality factors of 108, 210 and 78

108=2×2×3×3×3
210=2×3×5×7
78=2×3×13

Decompose 64 and 108 into prime factors and find out the number of factors

64 = 2 × 2 × 2 × 2 × 2, 1, 2, 4, 8, 16, 32, 64, a total of 7 factors
108 = 2 × 2 × 3 × 3, 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, 108 are 12 factors

If a and B decompose the prime factors a = 2 × 3 × 5 and B = 3 × 5 × 7, then the least common multiple of a and B is The greatest common divisor is ．

A = 2 × 3 × 5, B = 3 × 5 × 7, the common prime factors of a and B are: 3 and 5, the unique prime factor of a is 2, the unique prime factor of B is 7, then the greatest common factor of a and B is: 3 × 5 = 15, the least common multiple of a and B is: 3 × 7 × 2 × 5 = 210; so the answer is: 210, 15

If a and B are decomposed into prime factors, a = 2 * 3 * 5 * m, = 2 * 3 * 7 * m, then the greatest common divisor and the least common multiple of ab

a=2*3*5=30
b=2*3*7=42
Least common multiple: 210
Greatest common divisor: 6

The prime factors of AB decomposition are: a = 2 * 7 * 11, B = 5 * 7 * 11. The greatest common factor () and the least common multiple () of ab

A=2×7×11,B=5×7×11
Then:
A. The greatest common divisor of B is: [7 × 11 = 77]
A. The least common multiple of B is: [2 × 5 × 7 × 11 = 770]

The sum of the greatest common factor and the least common multiple of a number is 56. The number is ()

The greatest common factor and the least common multiple of a number are itself
So this number is 56 / 2 = 28
The sum of the greatest common factor and the least common multiple of a number is 56. The number is (28)

The least common multiple of two numbers is 140, the greatest common factor is 4, one of which is 56, what is the other number?

140×4÷56=10

1. The greatest common divisor of two numbers is 1 and the least common multiple is 56. These two numbers are () and (), or () and ()
2. Cut a square cardboard with side length of 6cm into the largest circle, and cut off part of the area which accounts for ()% of the original square
3. A dripping faucet will drain 15 kilograms of water every day. According to this calculation, this faucet will waste () kilogram of water in the first quarter of this year

1. The greatest common divisor of two numbers is 1, and the least common multiple is 56. These two numbers are (7) and (8), or (1) and (56)
2. Cut a square cardboard with side length of 6cm into the largest circle, and cut off part of the area accounting for (21.5%) of the original square
3. A dripping faucet will drain 15 kg of water every day. According to this calculation, this faucet will waste (1350) kilogram of water in the first quarter of this year
If you don't understand this question, you can ask,

What is the greatest common factor of 24 and 28 The least common multiple is ．

24 = 2 × 2 × 2 × 3, 28 = 2 × 2 × 7, so the greatest common divisor of 24 and 28 is 2 × 2 = 4, the least common multiple is 2 × 2 × 2 × 3 × 7 = 168, so the answer is: 4168