Decomposition factor: 16 (x + y) ^ 2-24 (x + y) + 9

16(x+y)^2-24(x+y)+9
=[4﹙x＋y﹚－3]²
=﹙4x＋4y－3﹚²

Decomposition factor: 9 (2x-y) ^ 2-16 (x + 2Y) ^ 2
Answer before 12 o'clock today. This is an arithmetic problem. Please answer in detail

9(2x-y)²-16(x+2y)²
The original formula = [3 (2x-y)], # 178; - [4 (x + 2Y)], # 178;
=[3（2x-y)+4(x+2y)][3(2x-y)-4(x+2y)]
= (6x-3y+4x+8y) (6x-3y-4x-8y)
=(10x+5y)(2x-11y)
=5(2x+y)(2x-11y)

Minus ten and one sixth times nine and five sixth square difference formula

Minus ten and one sixth times nine and five sixth
=-[10 + 1 / 6] [10-1 / 6]
=-[10-178; - (1 / 6) & 178;]
=-[1 / 100-36]
=-99 and 35 / 36

Please use the square difference formula to find (1-1 / 4) times (1-1 / 9)... Times (1-10000 / 1)

=(1-1/2^2)(1-1/3^2)…… (1-1 / 100 ^ 2) = (1 + 1 / 2) (1-1 / 2) (1 + 1 / 3) (1-1 / 3) (1+1/100)(1-1/100)=3/2×1/2×4/3×2/3…… 101/100×99/100=(3/2×4/3…… 101/100)×(1/2×2/3×99/100)=101/2×1/100=101/20...

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Decomposition factor: 16 (x + y) ^ 2-24 (x + y) + 9