Calculation: (2m + n-p) (2m-n + P)
(- 2m + n-p) (2m-n-p) urgent~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
If the minus sign is put forward, it's urgent~~~~~~~~~~~~~~~~~
=-(2m-n+p)(2m-n-p)
=-[(2m-n)+p][(2m-n)-p]
=-[(2m-n)²-p²]
=-(4m²-4mn+n²-p²)
=p²-4m²+4mn-n²
What does (2m + n-p) (2m-n-p) equal
(2m+n-p)(2m-n-p)
=[(2m-p)+n][(2m-p)-n]
=(2m-p)²-n²
=4m²-4mp+p²-n²
You can ask me if you don't understand my answer!
(2m+n-p)( 2m+p-n)
The original formula = (2m) & sup2; + (n-p) & sup2;
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