Let a and B be two different real roots of the equation / lgx / = C, if a

Let a and B be two different real roots of the equation / lgx / = C, if a

Because the real numbers a and B are two different real roots of the equation / lgx / = C, and a

How to solve (lgx) ^ 2 = 1 with x ^ lgx = 10

If you add LG to the left and right sides, it is LG (x ^ lgx) = LG10. Because LG10 equals 1, the index of the X in front of LG (x ^ lgx) can be written in front of LG, so it is lgxlgx, that is, (lgx) ^ 2, equal to LG10, it is 1

The interval of lgx-1 x = 0 is ()
A. （0，1]B. （10，100]C. （1，10]D. （100，+∞）

Let f (x) = lgx-1x, ∵ f (1) = - 1, f (10) = 1-110 = 910, ∵ f (1) · f (10) < 0, and f (x) be continuous on (0, + ∞), so the interval of zero point of F (x) is (1,10], so C

5-lgx 1 / 2 + lgx 2 / 2 = 1

1/(5-lgx)+2/(1+lgx)=1
So: 1 + lgx + 2 (5-lgx) = (1 + lgx) (5-lgx)
The results show that: (lgx) ^ 2-5lgx + 6 = 0
The solution is lgx = 2 or lgx = 3
So: x = 100 or x = 1000