Quadratic factorization factor of 4a-12ab + 9b-c Come on, come on
The second power of 4A - 12ab + the second power of 9b - the second power of C
=(2a)²-2×2a×3b+(3b)²-c²
=(2a-3b)²-c²
=(2a-3b+c)(2a-3b-c)
Given that 14a2 + 9b2 − a + 12b + 5 = 0, find the value of (a − 2) 2A2 − B2
14a2+9b2−a+12b+5=0,14a2-a+1+9b2+12b+4=0,(12a-1)2+(3b+2)2=0,∴12a-1=0,3b+2=0,∴a=2,b=-23,∴(a−2)2a2−b2=0.
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