Let a = {X / (x + 3) (2-x)} > = 0, B = {X / x ^ - 4ax - (1-4a ^)

Let a = {X / (x + 3) (2-x)} > = 0, B = {X / x ^ - 4ax - (1-4a ^)

x/(x+3)(2-x)>=0 =>
1.x>0 and (x>-3 and x0

If the image of the function y = (A-3) X2 - (4a-1) x + 4A with respect to X has two intersections with the coordinate axis, then the value of a is ()
A. 3 or 0b. A ＞ - 140 and a ≠ 3C. 0 or - 140d. 3 or 0 or - 140

Because there are only two intersections between the image of the function y = (A-3) X2 - (4a-1) x + 4A and the coordinate axis, i.e. one intersection with the X axis and one intersection with the Y axis, if the function is quadratic, then b2-4ac = [(4a-1)] 2-4 (A-3) × 4A = 0, that is 40A + 1 = 0, the solution is a = - 140; if a = 0, the image of the quadratic function passes through the origin, which satisfies the meaning of the problem. If the function is primary, then A-3 = 0, so a = 3 Therefore, if there are only two intersections between the image of the function y = (A-3) X2 - (4a-1) x + 4A and the coordinate axis, then a = 3 or 0 or - 140

1. Factorization: x ^ 2 + 6x+___ =(x+3)^2; a^2-4a+4=____ 2. The result of Factoring: X (x + 4) + 4 is_____ .
3. The result of factoring polynomial 2mx ^ 2-4mxy + 2My ^ 2 is________ .
4. Decomposition factor (a + b) ^ 2-6 (a + b) + 9=_______ .
5. Factorization: A ^ 2-B ^ 2-2b-1=______ .

1. Factorization factor: x ^ 2 + 6x + 9 = (x + 3) ^ 2; a ^ 2-4a + 4 = (A-2) ^ 2.2. Factorization factor: X (x + 4) + 4 results in (x + 2) ^ 2.3. Factorization factor 2mx ^ 2-4mxy + 2My ^ 2 Results in 2M (X-Y) ^ 24. Factorization factor (a + b) ^ 2-6 (a + b) + 9 = (a + B-3) ^ 2.5. A ^ 2-B ^ 2-2b-1 = (a + B + 1) (a-b-1)

Factorization: x ^ 2 + 6x+_____ =（x+3）^2；a^2-4a+4=______

x^2+6x+9=（x+3）^2
a^2-4a+4=(a-2)^2