A focus coordinate (- 3,0) a vertex coordinate (0,5) to find the trajectory equation of the ellipse)

The solution can be obtained from the meaning of the title
a^2-b^2=(-3)^2=9
b=5
So a ^ 2 = 34
The equation of ellipse is x ^ 2 / 34 + y ^ 2 / 25 = 1

The trajectory equation of the endpoint of the minor axis of a moving ellipse with the line x = - 2 as the guide line and the origin as the corresponding focus is
I don't understand

Let the endpoint of the minor axis be (x, y). Since the major axis of the obvious ellipse is the X axis, then B is the absolute value of Y, a = x + 2, C = X. then because a ^ 2 = B ^ 2 + C ^ 2, we get y ^ 2 + x ^ 2 = (x + 2) ^ 2, we get y ^ 2 = 4x + 4. This is its trajectory equation. The meaning of ABC is semi major axis, semi minor axis and semi focal length

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A focus coordinate (- 3,0) a vertex coordinate (0,5) to find the trajectory equation of the ellipse)