As shown in the figure, the straight lines AB, CD and EF all pass through point O, and ab ⊥ CD and og bisect ∠ BOE. If ∠ EOG = 25 ∠ AOE, calculate the degrees of ∠ EOG, ∠ DOF and ∠ AOE

As shown in the figure, the straight lines AB, CD and EF all pass through point O, and ab ⊥ CD and og bisect ∠ BOE. If ∠ EOG = 25 ∠ AOE, calculate the degrees of ∠ EOG, ∠ DOF and ∠ AOE

∫ EOG = 25 ∠ AOE, og bisection ∠ BOE, ∫ BOE = 45 ∠ AOE, ∫ AOE + ∠ BOE = 95 ∠ AOE = 180 °, ∫ AOE = 100 °, ∫ BOE = 45 ∠ AOE = 45 × 100 ° = 80 °, ∫ EOG = 40 °, ∫ ab ⊥ CD, ∫ EOF = 180 °, ∫ DOF = 180 ° - ∠ BOE - ∠ BOD = 180 ° - 80 ° - 90 ° =

As shown in the figure, the lines AB, CD and EF intersect at point O, og bisects ∠ BOF, and CD ⊥ EF, ∠ AOE = 70 ° to calculate the degree of ∠ dog

∫ AOE = 70 °, ∫ BOF = ∠ AOE = 70 ° and ∫ og bisection ∠ BOF, ∫ GOF = 12 ∠ BOF = 35 ° and ∫ CD ⊥ EF, ∫ EOD = 90 ° and ∫ dog = 180 ° - GOF - EOD = 180 ° - 35 ° - 90 ° = 55 °

As shown in Figure 11, lines AB, CD and EF intersect at point o,

From the meaning of the title, we can know that ∠ AOE = 180-62 = 118, and ∠ BOC = 90, then: ∠ COE = 90-62 = 28, ∠ EOG = ∠ AOG = 118 / 2 = 59, ∠ cog = ∠ goe - ∠ COE = 59-28 = 31