As shown in the figure, it is known that the straight line AB and CD are cut by the straight line EF. If ∠ BMN = ∠ DNF, ∠ 1 = ∠ 2, then MQ ‖ NP. Why?

As shown in the figure, it is known that the straight line AB and CD are cut by the straight line EF. If ∠ BMN = ∠ DNF, ∠ 1 = ∠ 2, then MQ ‖ NP. Why?


It is proved that: ∵ BMN = ∵ DNF, ∵ 1 = ∵ 2 (known), ∵ BMN + ∵ 1 = ∵ DNF + ∵ 2, that is, ∵ PNF = ∵ QMN ∥ MQ ∥ NP



1 as shown in the figure, it is known that AB is parallel to CD, and the straight line EF intersects AB, and CD is equally divided between M, N, MP ∠ EMP, and NQ ∠ MND. Try to judge the position relationship between MP and NQ, and explain the reason
2 as shown in the figure, De is parallel to BC, angle D: angle DBC = 2:1, angle 1 = angle 2, calculate the degree of angle DEB
Figure 1


DE‖BC
The results show that ∠ e = ∠ 1, ∠ D + ∠ DBC = 180 degree
And ∵ - D: ∵ - DBC = 2:1, ∵ - D = 120 ° and ∵ - DBC = 60 °
∠1 = ∠2,∴∠1 = 30°
∠E = ∠1 = 30°



In square ABCD, m, N, P and Q are points on edges AB, BC, CD and Da respectively, and MP is perpendicular to NQ. Are MP and NQ equal
RT, the picture can't be transmitted. It's not the midpoint, any point


I don't know if you're talking about this graph? Now I try to prove that QF is perpendicular to F, and then PE is perpendicular to ab. because the quadrilateral ABCD is a square, QF is perpendicular to BC, PE is perpendicular to AB, so PE = ad = AB = = QF, and PE and QF are perpendicular to each other. MP and QN are perpendicular, and the intersection of MP and QF is a pair of vertex angles. It's easy to conclude that angle 1 equals angle 2, QF is perpendicular to BC, PE is perpendicular to ab, So angle 3 is equal to angle 4, QF is equal to PE. Now we have formed the "angle, side and angle theorem" that two angles are equal on one side. Triangle QFN is equal to triangle PEM, so QN is equal to PM



If there are two points m and N on the straight line a, and Mn = 14cm, the other point q is also on the straight line a, and NQ = 5cm, then MQ =? Fast


If q is on Mn, MQ = mn-nq = 14-5 = 9cm
If q is on the Mn extension line, MQ = Mn + NQ = 14 + 5 = 19cm
in summary
MQ = 9cm or 19cm