The center of the circle x ^ 2 + y ^ 2-4x + 2Y = 0 is () and the radius is ()

The center of the circle x ^ 2 + y ^ 2-4x + 2Y = 0 is () and the radius is ()


Center type: (X-2) &# 178; + (y + 1) &# 178; = 5 so: the center is (2, - 1) radius = √ 5 ~ always 523 for you, I wish you progress in your study ~ ~ ~ if you agree with my answer, please click the [adopt as satisfactory answer] button in time ~ ~ the mobile phone questioner can comment "satisfied" on the client ~ ~ ~ your adoption is my driving force ~ ~ ~ if there are any new questions, Please ask me for help. The answer is not easy. Please understand~~



If the line x-5y + 3 passes through the center of the circle X & # 178; + Y & # 178; - MX + 2Y + (M & # 178 / 4) - 1 = 0, then M =?


x²+y²-mx+2y+(m²/4)-1=0
(x-m / 2) ^ 2 + (y + 1) ^ 2 = 2
The center of the circle (M / 2, - 1) is substituted into the linear equation
M / 2-5 (- 1) + 3 = 0 leads to M = - 16



Given that the equation of a circle is (x + 1) &# 178; + (Y-3) &# 178; = 9, what is the center coordinate and radius of the circle


The center coordinate of the circle is (- 1,3), and the radius of the circle is 3