What is the solution of X & # 178; - 13X + 12 = - 4x & # 178; + 18?
x²-13x+12=-4x²+18
x²-13x+12+4x²-18=0
5x²-13x-6=0
△=169+4*5*6=17*17
x=(13±17)/10
x=2
x=-2/5
x²-4x+2=0
Answer: X & # 178; - 4x + 2 = 0
x²-4x+4=2
(x-2)²=2
Square both sides
x-2=±√2
x=2±√2
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- 1. x²+4x+3
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- 4. It is proved that no matter what the value of K is, there are two intersections between the line L: kx-y-4k + 2y-3 = 0 and the circle C: X & # 178; + Y & # 178; - 6x-8y + 21 = 0 It is proved that no matter what the value of K is, there are two intersections between the line L: kx-y-4k + 2y-3 = 0 and the circle C: X & # 178; + Y & # 178; - 6x-8y + 21 = 0
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- 10. The known set a = {x | x2-4x + 2A + 6 = 0}, B = {x | x}
- 11. As shown in the figure, it is known that the image of quadratic function y = x2 + BX + C passes through points (- 1,0), (1, - 2). When y increases with the increase of X, the value range of X is___ .
- 12. It is known that the image of quadratic function y = x + bx-3 passes through the point (- 2,5)
- 13. As shown in the figure, it is known that the image of quadratic function y = x2 + BX + C passes through points (- 1,0), (1, - 2). When y increases with the increase of X, the value range of X is___ .
- 14. How to fill in the brackets of X & # 178; + 1 / X & # 178; = (x + 1 / x) & # 178; - () = (x-1 / x) & # 178; + ()?
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