Mathematics problem of grade one 1. Add brackets in the polynomial m4-2m2n2-2m2 + 2n2 + N4; 【1】 Combine the four terms and put them in the brackets with "+" in front 【2】 Combine the quadratic terms and put them in the front with "-" 2. Given 2x + 3y-1 = 0. Find the value of 3-6x-9y 3. Let the quadratic power of X + xy = 3. The quadratic power of XY + y = - 2. Find the value of the quadratic power of 2x - xy-3y 4. Write the polynomial 10x ^ 3-7x ^ 2Y + 4xy ^ 2 + 2Y ^ 3-5 as the difference between two polynomials, that is, the subtraction does not contain the letter y 5. Add 2x ^ 2 + 3x-6 as required 【1】 Write the sum of a monomial and a binomial; 【2】 Write the difference between a monomial and a binomial 6. Write the polynomial x ^ 3-6x ^ 2Y + 12xy ^ 2-8y ^ 3 + 1. Into the sum of two integers, so that one of them does not contain the letter X 7. Let 3x ^ 2-x = 1. Find the value of 9x ^ 4 + 12x ^ 3-3x ^ 2-7x + 2000 By the way, let's talk about the rule of adding brackets

Mathematics problem of grade one 1. Add brackets in the polynomial m4-2m2n2-2m2 + 2n2 + N4; 【1】 Combine the four terms and put them in the brackets with "+" in front 【2】 Combine the quadratic terms and put them in the front with "-" 2. Given 2x + 3y-1 = 0. Find the value of 3-6x-9y 3. Let the quadratic power of X + xy = 3. The quadratic power of XY + y = - 2. Find the value of the quadratic power of 2x - xy-3y 4. Write the polynomial 10x ^ 3-7x ^ 2Y + 4xy ^ 2 + 2Y ^ 3-5 as the difference between two polynomials, that is, the subtraction does not contain the letter y 5. Add 2x ^ 2 + 3x-6 as required 【1】 Write the sum of a monomial and a binomial; 【2】 Write the difference between a monomial and a binomial 6. Write the polynomial x ^ 3-6x ^ 2Y + 12xy ^ 2-8y ^ 3 + 1. Into the sum of two integers, so that one of them does not contain the letter X 7. Let 3x ^ 2-x = 1. Find the value of 9x ^ 4 + 12x ^ 3-3x ^ 2-7x + 2000 By the way, let's talk about the rule of adding brackets

1,+（m4-2m2n2+n4）-（2m2-2n2）
2, because 2x + 3y-1 = 0
So both sides * - 3 at the same time
3-6x-9y=0
So 3-6x-9y = 0
3, because x ^ 2 + xy = 3, y ^ 2 + xy = - 2
So x ^ 2-y ^ 2 = 5
So 2x ^ 2-2y ^ 2 = 10
And because y ^ 2 + xy = - 2
So the original formula is 12
So the original formula is 12
4,
（-7x^2y+4xy^2+2y^3）-（-10x^3+5）
5. (Mingtian continues!)

Removing bracket and denominator
(3 / 2x-1) - (6 / 10x + 1) = (4 / 2x + 1) - 1 bracketed is the fraction

At the same time, multiply by (2x-1) (10x + 1) (2x + 1)
3（10x-1)(2x+1)-6(2x-1)(2x+1)=4*(2x-1)(10x+1）
3 (20x square + 8x-1) - 6 (4x Square-1) = 4 * (20x square-8x-1)
(60-24) x square + 24x-3 + 6 = 80x square - 32x-4
(80-44) xsquare - (32-24) x-4-3 = 0
34x square - 8x-7 = 0