1. Given that the solutions of equation 4x + 2m = 3x + 1 and equation 3x = 2m = 6x + 1 are the same, then M =? 2. If (7y-4 / 2) and (y + 2 / 5) - 2 are opposite to each other, then y =? 2? This is the two exercises of the equation of one variable of grade one in junior high school

1. Given that the solutions of equation 4x + 2m = 3x + 1 and equation 3x = 2m = 6x + 1 are the same, then M =? 2. If (7y-4 / 2) and (y + 2 / 5) - 2 are opposite to each other, then y =? 2? This is the two exercises of the equation of one variable of grade one in junior high school

If the plus sign is 1.3x "=" 2m = 6x + 1,
x+2m=1
3x-2m=-1
x=0,m=1/2
2.7y-2=y+0.4-2,y=1/15

Given the set a = {(x, y) | 3x-7y = - 5}, B = {(x, y) | 2x + 9y = 40}, find a ∩ B (by enumeration)

It is to solve the equations
3x-7y=-5 1)
2x+9y=40 2)
1)*2:6x-14y=-10 3)
2)*3:6x+27y=120 4)
4) - 3): 41Y = 130, get: y = 130 / 41
Substituting 1): x = (7y-5) / 3 = 235 / 41
So a ∩ B = {(235 / 41130 / 41)}

The graph represented by equation x2 + 6xy + 9y2 + 3x + 9y-4 = 0 is ()
A. Two overlapping lines B. two parallel lines C. two intersecting lines D. two perpendicular lines

The original formula can be reduced to (x + 3Y + 4) (x + 3y-1) = 0, so x + 3Y + 4 = 0, x + 3y-1 = 0, the slopes of two straight lines are equal, and there is no common point, which is two parallel straight lines

Mathematics problem of grade one in junior high school
If a = the square of 3x - the square of 4Y, B = - the square of Y - the square of 2x + 1, then A-B = ② 3 (the cubic of a - the square of a + the square of half AB) - half (the cube of 6A + the square of 4A + the square of 3AB) ③ if (the square of 3x - 2) - (the square of 3x - y) = - 2, find the algebraic formula (x + y) + 3 (X-Y) - 4 (x + Y-2)

If a = 3x squared - 4Y squared, B = - y squared - 2x squared + 1,
Then A-B = 3x & # 178; - 4Y & # 178; + Y & # 178; + 2x & # 178; - 1
=5x²-3y²-1;
② 3 (cubic of a - square of a + square of half AB) - half (cubic of 6A + square of 4A + square of 3AB)
=3a³-3a²b+3ab²/2-3a³-2a²b-3ab²/2
=-5a²b;
③ If (3x's square-2) - (3x's square-y) = - 2, find the algebraic formula (x + y) + 3 (X-Y) - 4 (x + Y-2)
3x²-2-3x²+y=-2;
y=0;
Original formula = x + 3x-4x + 8
=8;
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