x²+4x+3

x²+4x+3

x²+4x+3
=（x+3)(x+1)

What is the solution of X & # 178; + 4x-3 = 0

x²+4x-3=0
x²+4x+4=7
(x+2)²=7
x+2=±√7
x=-2±√7
Namely
x1=-2+√7
x2=-2-√7

|The functional solution of X & # 178; - 4x + 3 |

| x²-4x+3| =|( x-3)(x-1)| =0
x=3 x=1

If the function y = - 2x & # 178; + MX-3 is a decreasing interval on [- 1, + ∞], then the value range of M is known as f (x) = x & # 178; + 2 (1-A) x + 2 is a decreasing function on (- ∞, 4], and the value range of real number a is known as f (x) = 1 + (LX - x) / 2 (- 2 ＜ x ≤ 2); the function is expressed in the form of piecewise function; the function image is drawn; the function value range is written to solve these problems. Thank you, please write clearly

If the function y = - 2x & # 178; + MX-3 is a decreasing interval on [- 1, + ∞], then the value range of M
y=-2x²+mx-3
=-2(x-m/4)²-3+m²/8
When the opening is downward, the axis of symmetry x = m / 4, and x > m / 4, it is a single minus interval
Therefore, M / 4