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The common tangent of circle x ^ 2 + y ^ 2 = 1 and circle x ^ 2 + y ^ 2-6x-8y + 9 = 0 are
(x+3)^2+(y+16)^2=16
There are four tangent lines
The number of tangent lines of two circles x ^ 2 + y ^ 2-6x + 16y = 0 and x ^ 2 + y ^ 2 + 4x-8y-44 = 0
(x-3)²+(y+8)²=73
Center (3, - 8), R1 = √ 73
(x+2)²+(y-4)²=64
Center (- 2,4), R1 = 8
Center distance d = √ (5 & sup2; + 12 & sup2;) = 13
So | R1-R2|
There are two points on the plane, a (- 1,0), B (1,0), P (x, y) is a point on the circle x square + y square - 6x-8y + 21 = 0,
Finding the range of 3x + 4Y
X square + y square range
Find s = PA square + Pb square range
Finding the range of Y / (x + 4)
A. If 1 is less than y and greater than - 1, then the range of 3x + 4Y is greater than - 4 and less than 4x square + y square is less than 1. If s = PA square + Pb square is greater than - 4 and less than 4, then the range of Y / (x + 4) is less than 1 / 4 and more than - 1 / 4P (x, y) x square + y square - 6x -
Given that there are four common tangents between circle (x-3) ^ 2 + y ^ 2 = 1 and circle x ^ 2 + y ^ 2-8y + B = 0, the value range of B is?
The center of the first circle is (3,0) and the radius is 1;
The second circle simplification: x ^ 2 + (y-4) ^ 2 = 16-b, the center of the circle is (0,4), and the radius is √ (16-b);
Distance between the centers of two circles: under the root sign (3 ^ 2 + 4 ^ 2) = 5;
Because there are four common tangents, the two circles are separated, and the radius of the second circle is less than 4 and greater than 0;
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RELATED INFORMATIONS
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