In polynomials X & sup2; + 2kxy-3y & sup2; + X-12, the term without XY is used to find the value of K & sup3; - 1 Please answer carefully

In polynomials X & sup2; + 2kxy-3y & sup2; + X-12, the term without XY is used to find the value of K & sup3; - 1 Please answer carefully

If the term does not contain XY, its coefficient is 0
So 2K = 0
k=0
So K & sup2; - 1 = 0-1 = - 1

When k = the polynomial X & # 178; - 3kxy-3y & # 178; - 2xy-8 does not contain XY term?

Polynomials should be combined with similar terms and reduced to: the original formula = x & # 178; - (3K + 2) xy-3y & # 178; - 8
The coefficient of XY is 0
∴3k+2=0
∴k=-2/3
Think more about the concept, this problem is not difficult!

When m < 0, the absolute value of the algebraic formula m ^ 3 - m ^ 2 / M divided by the absolute value of M=

When m < 0,
The absolute value of the algebraic formula m ^ 3 - m ^ 2 / M divided by M
=|m|/ (|m^3|-m^2/m)
=-m/ (-m^3-m^2/m)
=-m/ (-m^2-m)
=1/ (m+1)

The equation | X-2 | + | x-3 | = a about X is known. The existence condition of a is studied and the solution of this equation is discussed

(1) When x ≤ 2, the original formula = 2-x + 3-x = a ﹥ a = 5-2x ﹥ a ≥ 1 (2) when 2 < x ≤ 3, the original formula = X-2 + 3-x = a ﹥ a = 1 (3) when x > 3, the original formula = X-2 + x-3 = a ﹥ a = 2x-5 ﹥ a > 1

The complement problem of signed binary numbers
How to determine the complement of an unsigned binary number
And how to calculate the addition and subtraction of unsigned binary numbers?

The original code, inverse code and complement code are applied to the number of "you" symbols
For the binary number without sign, there is no complement