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The solution of quadratic equation of one variable? X-1] - 3 [1-4x] - 4 = 0 is
It should be 0.5
It is known that x1x2 is two unequal real roots of the quadratic equation KX + 4x - 3 = 0 with respect to X
1, find the value range of K
Δ = b square - 4ac = 4 * 4-4 * k * (- 3) > 0
The solution is k > - 4 / 3
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