3 (x square-4x) square-48 Factorization

3 (x square-4x) square-48 Factorization

Original formula = 3 [(X & # 178; - 4x) &# 178; - 16]
=3(x²-4x+4)(x²-4x-4)
=3(x-2)²(x²-4x-4)

How to factorize 4x Λ 2-4x-5 = 0

You want to solve the equation formula method: 4x & # 178; - 4x-5 = 0, Δ = 16 + 80 = 96 > 0x = (4 ± 4 √ 6) / 8 = (1 ± √ 6) / 2, so: X1 = (1 + √ 6) / 2, X2 = (1 - √ 6) / 2 matching method: 4x & # 178; - 4x-5 = 0x & # 178; - x = 5 / 4x & # 178; - x + (1 / 2) & # 178; = 5 / 4 + 1 / 4 (x-1 / 2) & # 178; = 6 / 4x-1 / 2 =

x^4-4x^3+10x^2-12x+9
Factorization, and X is a rational number

x^4-4x^3+10x^2-12x+9
=(x^4-4x^3+6x^2-4x+1)+(4x^2-8x+4)+4
=(x-1)^4+4(x-1)^2+4
=[(x-1)^2+2]^2>=4
therefore
The minimum value of x ^ 4-4x ^ 3 + 10x ^ 2-12x + 9 is 4

How to solve 2.4x-9.8 = 1.4x-9
You understand what I'm typing in pinyin

2.4x-9.8=1.4x-9 2.4x-1.4x=9.8-9 x=0.8