If (X-Y) 2 + | 5x-7y-2 | = 0, then x=______ ，y=______ ．

If (X-Y) 2 + | 5x-7y-2 | = 0, then x=______ ，y=______ ．

∵ (X-Y) 2 + | 5x-7y-2 | = 0, ∵ x − y = 05x − 7Y − 2 = 0, the solution is x = y = - 1

Given that − 47y2m − 5xn + 1 and 35xm + 2yn − 2 are of the same kind, then M-N = ()
A. -1B. 1C. -7D. 7

According to the meaning: 2m − 5 = n − 2n + 1 = m + 2, the solution: M = 6N = 7, then M-N = 6-7 = - 1

How to write 2x-3y = 0, 5x-7y = 1

(1)2x=3y x-3y/2 y=2x/3
Thank you!

1.（x-3y)(x+3y)-(x-3y)^2 2.98^2 3.(2x-y-3)(2x+y+3) 4.50.1^2 5.(5x+7y)^2-(5x-7y)^2
Note that ^ is followed by the square, which is calculated by the square difference formula

1.（x-3y)(x+3y)-(x-3y)^2
=(x-3y)[(x+3y)-(x-3y)]
=6y(x-3y)
2.98^2
=(100-2)^2
=100^2-2x100x2+2^2
=10000-400+4
=99604
3.(2x-y-3)(2x+y+3)
=(2x)^2-(y+3)^2
=4x^2-y^2-6y-9
4.50.1^2
=(50+0.1)^2
=50^2+2x50x0.1+0.1^2
=2500+10+0.01
=2510.01
5.(5x+7y)^2-(5x-7y)^2
=[(5x+7y)+(5x-7y)][(5x+7y)-(5x-7y)]
=140xy