5x = 3Y, X-Y = 4 write the process of equations, 1 / 2x = - 2 / 3Y, 2x + y = 7 write the process of equations

5x = 3Y, X-Y = 4 write the process of equations, 1 / 2x = - 2 / 3Y, 2x + y = 7 write the process of equations

1. 5x = 3yx-y = 4, substituting x = 4 + y into: 5 (4 + y) = 3y20 + 5Y = 3yy = - 10x = - 6, that is, x = - 6, y = - 102, 1 / 2x = - 2 / 3Y, 3x = - 4y2x + y = 7, substituting y = 7-2x into: 3x = - 4 (7-2x) 3x = - 27 + 8x5x = 27x = 27 / 5Y = 7-2 × 27 / 5 = - 19 / 5  x = 27 / 5 = 5.4y = - 19 / 5 = - 3.8

-2x+3=5x-4

-2x-5x=-4-3
7x=7
x=1
If you have any new questions, please don't send them in the form of follow-up questions, send them to me for help or send them to the question link address,

3(4-2x)=5x+23
5（x+8)-5=6(2x-7)
4(2y+3)+5(y-2)=8(1-y)

Solution
3(4-2x)=5x+23
12-6x=5x+23
-6x-5x=23-12
-11x=11
x=-1
5(x+8)-5=6(2x-7)
5x+40-5=12x-42
5x+35=12x-42
5x-12x=-35-42
-7x=77
x=-11
4(2y+3)+5(y-2)=8(1-y)
8y+12+5y-10=8-8y
13y+2=8-8y
13y+8y=8-2
21y=6
y=2/7

2X of 3 + 3 = 5x-2 of 4

2X of 3 + 3 = 5x-2 of 4 multiply both sides by 12 at the same time
8x+36=15x-24
15x-8x=36+24
7x=60
X = 60 / 7