X + y + Z = 35 2x-y = 5 1 / 3 y = 1 / 2 Z

X + y + Z = 35 2x-y = 5 1 / 3 y = 1 / 2 Z

The solution is as follows: x = 10, y = 15, z = 10
From 2x-y = 5, we can get x = (y + 5) / 2
From Y / 3 = Z / 2, we can get z = (2Y) / 3
By substituting X and Z into x = y = z = 35, we can get
[(y+5)/2]+y+[(2y)/2]=35
It can be obtained by solving the linear equation of one variable
y=15
Then we can calculate x = 10, z = 10
The premise is that the landlord can solve the equation of first degree with one variable
I don't know if I understand

Calculate (x + y) (- 2x-1 / 2 y)
(2x + 1) (x-1) (2x-3) is equal to 4x & # 179; - 8x & # 178; + X + 3;? If not, please answer

(x + y) (- 2x-1 / 2 y)
=-2x²-1/2xy-2xy+1/2y²
=-2x²-3/2xy+1/2y²
(2x+1)(x-1)(2x-3)
=(2x²+x-1)(2x-3)
=4x³-6x²+2x²-3x-2x+4
=4x³-4x²-5x+3;

Substituting elimination method to solve equation: 3x-2 / 1y = 1 2x + y = 2

3x-y/2=1 (1)
2x+y=2(2)
From (2): y = 2-2x into (1)
3x-(2-2x)/2=1
3x-(1-x)=1
3x-1+x=1
4x=2
x=1/2
Substituting (2) to get:
1+y=2
y=1
x=1/2
y=1