Simplification: [(x ^ 2 + 18x + 72) / (x + 12) - (x ^ 2 + 5x-6) / (x-1)] · (x ^ 3-2x ^ 2-x + 1)

Simplification: [(x ^ 2 + 18x + 72) / (x + 12) - (x ^ 2 + 5x-6) / (x-1)] · (x ^ 3-2x ^ 2-x + 1)

〔（x^2+18x+72)÷（x+12)-(x^2+5x-6)÷(x-1)〕·(x^3-2x^2-x+1)
= [(x+12)(x+6)/(x+12) - (x-1)(x+6)/(x-1)] ·(x^3-2x^2-x+1)
= [(x+6) - (x+6)] )·(x^3-2x^2-x+1)
= 0 ·(x^3-2x^2-x+1)
= 0

(2x-2 / 1y & # 178;) &# 178;

(2x-2 / 1y & # 178;) &# 178;
=The fourth power of 4x & # 178; - 2XY & # 178; + 1 / 4Y

Given X & # 178; + Y & # 178; + 5 / 4 = 2x + y, find the value of X & # 178; + Y & # 178

Find the value of X & # 178; + Y & # 178; + 5 / 4 = 2x + y
x²-2x+1+y²-y+1/4=0
(x-1)²+(y-1/2)²=0
x=1,y=1/2
x²+y²=1+1/4=5/4

X-Y = - 1, x + 4Y = 4, x, y 0.2x + 0.5y = 1, 0.4x + 0.1Y = 2, x, y

X-Y = - 1 (1)
x＋4y＝4,(2)
(2) (1) × 4
8y=8
y=1
Substituting (2) to get:
x=0
So: x = 0; y = 1
0.2x + 0.5y = 1 / 5 (1)
0.4x + 0.1Y = 2 / 5 (2)
(1) 2 - (2)
0.9y=0
y=0
Substituting (1) to get:
x=1
So, x = 1; y = 0