In the polar coordinate system, we know two points a (6, π / 6) B (6, 2 π / 3) to find the polar coordinates of the midpoint of ab,

In the polar coordinate system, we know two points a (6, π / 6) B (6, 2 π / 3) to find the polar coordinates of the midpoint of ab,

In the polar coordinate system, if the points a (3,2 π / 3) and B (4,π / 6) are known, then the polar coordinates of the central line of line AB are?
I figured out P = 5 myself, but the value of Tan is strange

In the polar coordinate system, if the polar coordinates of two points a and B are (3, π 3), (4, π 6), then the area of △ AOB (where o is the pole) is______ ．

According to the meaning of the question, ∠ AOB = π 6, Ao = 3, OB = 4, where o is the pole, the area of ∧ AOB is 12.3.4.sin π 6 = 3

As shown in the figure, the coordinates of a and B in △ AOB are (2,4), (6,2) respectively. Find the area of △ AOB. (the area of △ AOB can be regarded as the area of a rectangle minus the area of some small triangles.)

The intersection of CE and CF is C, and the perpendicular foot is e, f ∵ a (2,4), B (6,2) ∵ OE = AC = 4, EA = CB = BF = 2, of = 6, ∵ secfo = 6 × 4 = 24 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp (2) s △ AOE = 12 × 4 × 2 = 4 (4 points) s △ ACB = 12 × 4 × 2 = 4 & nbsp (6 points) s △ BOF = 12 × 6 × 2 = 6 & nbsp (8) s △ AOB = secfo-s △ aoe-s △ acb-s △ BOF = 24-4-4-6 = 10 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp (10 points) the AOB area is 10