Solving the right focus polar coordinate equation of mathematical conic Is it the same
Taking the focus F as the pole o, passing through the pole as the vertical line of the collimator L, intersecting with L at h, taking the reverse extension line ox of Oh as the polar axis, the polar coordinate system is established
Let the distance between the focus F and the guide line l be p, P (ρ, θ) be any point on the conic, connect OP and make PD ⊥ L, PQ ⊥ ox, then OP = ρ, ∠ XOP = θ
According to the definition of conic curve, there are │ op │ / │ PD │ = e, and │ PD │ = │ HQ │ = │ Ho │ + │ OQ │ = P + ρ & # 8226; Cos θ
So ρ / (P + ρ &; Cos θ) = E. that is, ρ = EP / (1-e &; Cos θ)
In the polar coordinate system, the polar coordinate equation of the line passing through the center of the circle P = 6cos @ and perpendicular to the polar axis is
p^2=6pcos@
x^2+y^2=6x
x^2-6x+y^2=0
x^2-6x+9-9+y^2=0
(x-3)^2+y^2=9
So the center of the circle (3,0)
The line is perpendicular to the polar axis
So the straight line is: x = 3
Polar equation: PCOS @ = 3
For the sake of my being so serious, just give me some points~