If for any real number a, f (Sina + COSA) = sinacosa, find f (0) + F (1)?

If for any real number a, f (Sina + COSA) = sinacosa, find f (0) + F (1)?


Let x = Sina + cosa
x²=sin²a+cos²a+2sinacosa
=1+2sinacosa
sinacosa=(x²-1)/2
f(x)=(x²-1)/2
f(0)+f(1)=-1/2+0=-1/2



In the polar coordinate system, the distance between the point m (√ 5, arctan2) and the straight line ρ (COS θ + sin θ) = 1 is 0


In the rectangular coordinate system, if the coordinate of m point is (1,2) and the linear equation is x + y = 1, then the distance between M and the straight line is √ 2



In polar coordinates, the maximum distance between the point on the circle ρ = 2cos (θ + π / 4) and the point on the straight line ρ sin (θ + π / 4) = √ 2 is -?


Circle ρ = 2cos (θ + π / 4)
ρ=√2cosθ-√2sinθ
x^2+y^2=√2x-√2y
(x-√2/2)^2+(y+√2/2)^2=1
Center (√ 2 / 2, - √ 2 / 2), radius r = 1
Straight line ρ sin (θ + π / 4) = √ 2
x+y=2
The distance from the center of the circle (√ 2 / 2, - √ 2 / 2) to x + y = 2
d=√2
The maximum distance is: 1 + √ 2



In polar coordinates, the distance from point (3, π 2) to line ρ sin (θ - π 4) = 22 is___ .


The point P (3, π 2) is transformed into P (0, 3). The straight line ρ sin (θ - π 4) = 22 is expanded into 22 (ρ sin θ - ρ cos θ) = 22, which is transformed into X-Y = 4, and the distance from point P to the straight line d = | 0-3-4| 2 = 722, so the answer is: 722