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The ratio of power consumption is () A.2:1 B.1:2 C.4:1 D:1:4
In the same circuit, u remains the same
In series, the resistance is 2R
In parallel, the resistance is R / 2
Power P = u ^ 2 / R
The ratio is 1:4
If the resistance of an electrical appliance is 100 Ω and the current passing through it is 1.2A, its heating power is w
Electric power = current ^ 2 × R
=144W (theoretical calculated value of DC current or RMS)
The total resistance of a DC circuit is 0.4 ohm. The electric power it provides to consumers is 40 kW and the voltage is 800 v. if it is replaced by superconducting material, the power and voltage remain unchanged, how much electric power can be saved?
AA analysis: P output = u? 0? 3 = 800? Gain I = 50a, P loss = I2R = 04? 2 = 1000W, save 1000W
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