Problem! An energy-saving lamp with a power of 10 watts (0.01 kW) costs 60 yuan; an incandescent lamp with a power of 60 watts (0.06 kW) costs 3 yuan, and its service life is the same. The electricity charge for more than 3000 hours is 0.5 yuan / kW / h. what kind of cost saving do consumers choose? Solution: the total cost of energy-saving lamp is Y1, and the total cost of incandescent lamp is Y2 ①Y1>Y2 Y1-Y2>0 X

Price difference divided by power difference

The power of an energy-saving lamp is 10 watts (0.01 kW), and the price is 60 yuan; the power of an incandescent lamp is 60 watts (0.06 kW), and the price is 3 yuan. The lighting effect of the two lamps is the same, and the service life is the same (more than 3000 hours). If the electricity price is 0.5 yuan / (KWH), which lamp can consumers choose to save money?
If the lighting time is x hours, the total cost of energy saving lamp is Y1 = 0.5 × 0.01x + 60 (1)
Similarly, the total cost of incandescent lamp can be written as y2 = (fill in) (2)
According to 1 and 2 functions, consider the following problems
(1) What is the value of X when Y1 = Y2
(2) Why is Y1 > Y2 when x is value
(3) Why is Y1 < Y2 when x is value

y2=0.5*0.06x+3
Y1=Y2
0.5*0.01x+60=0.5*0.06x+3----> 0.0025x=57 --->x=57/0.025=2280
That's 2280 hours, Y1 = Y2
10> 2280 hours, Y1