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The upper bottom of a trapezoid is 12.5cm. Reduce the lower bottom by 3.5cm and change it into a parallelogram. At this time, the area is reduced by 7cm. What is the area of the original trapezoid?
The height is 7 × 2 △ 3.5 = 4cm
The original trapezoid area is 12.5 × 4 + 7 = 57 square centimeters
In the parallelogram with an area of 24cm, the largest right angled trapezoid is 5cm in bottom and 4cm in height. What is the square of the remaining right angled triangle? There are several ways to solve it
Because the area of the parallelogram is 24, the height of the parallelogram is the same as that of the trapezoid, and the height is 4
Therefore, if the side length of a parallelogram is 6 and the bottom of a trapezoid is 5, then the bottom of a triangle is 6-5 = 1
Triangle area = 1 × 4 × 1 / 2 = 2
Or the trapezoid area = (6 + 5) × 4 △ 2 = 22
24-22=2
The top bottom of a trapezoid is 20cm. The top bottom is 5cm. Lengthen the top bottom by 5cm and increase the area by 20 square cm. What is the height of the trapezoid?
（20+5+5)/2*h-(20+5)/2*h=20,h=8
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