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In parallelogram ABCD, BD is perpendicular to ad, ad = 6cm, the area of parallelogram is 24, find the length of BD and AC
∵ s parallelogram ABCD = ad * BD = 24, ad = 6
∴BD=4
Connect AC with BD in o
Then do = 1 / 2bd = 2
AC=2AO=2√AD^2+DO^2=4√10
A group of adjacent sides of a parallelogram is 3cm and 6cm long, and the angle between the two sides is 60 degrees, then the area of the parallelogram is 0_____ cm²
If we make the height, we can get a right triangle with 3 hypotenuse. According to Pythagorean theorem, we can get the height as 3 √ 3 / 2,
According to the area formula of parallelogram: bottom * height = 6 * 3 √ 3 / 2 = 9 √ 3
So the area of the parallelogram is__ 9√3___ cm²
I want to ask how to calculate the height of 3 √ 3 / 2 with Pythagorean theorem
Please make a formula,
If the included angle is 60, the vertex angle of the new triangle is 30;
If the hypotenuse is 3, the right angle is 3 / 2
So using Pythagorean theorem, we can calculate the height = √ [3 + (3 / 2) &# 178;] = 3 √ 3 / 2
The area of a parallelogram is 3.2cm, and the area of a triangle with the same base and height is cm;
6 cm & sup2; (the area of a triangle is half the area of a parallelogram of equal height to it.)
In the parallelogram ABCD, the lengths of the two adjacent sides are 4cm and 6cm respectively, and their included angle is 60 degrees. Then how many cm are the lengths of the two diagonals respectively?
The length of the diagonal line opposite 60 ° is 8 times root 3 / 3, and the other length is 16 times root 3 / 3
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