Metal conduction refers to the directional movement of free electrons in the metal under voltage, but after the electrons in a power supply, a light bulb and a wire move Where does the electron go to the negative pole? Is there a new electron supplement or is the nucleus charged after the electron is removed

Metal conduction refers to the directional movement of free electrons in the metal under voltage, but after the electrons in a power supply, a light bulb and a wire move Where does the electron go to the negative pole? Is there a new electron supplement or is the nucleus charged after the electron is removed


···Man, the flow direction of electrons is from the negative pole to the positive pole... Well, in fact, the flow speed of electrons is very slow... It's about 1cm / s. The whole circuit is a cycle system, and the amount of electrons reaching the positive pole is the same as that flowing out of the negative pole. In the battery, electrons flow from the positive pole to the negative pole, forming a cycle
As for the nuclear problem, the electrons become free electrons after being charged, but they will be recaptured after the voltage disappears



AB is two insulated metal balls. A ball is positively charged and B ball is negatively charged. A copper wire is used to connect the two balls. The direction of the free electrons in the wire? The direction of the current?
Why?


The free electron is negatively charged, so it moves towards the a-ball
The direction of the current is the moving direction of the positive charge, and the negative charge moves to the ball a, which is equivalent to the positive charge moving to the opposite direction, that is, to the ball B, so the current is from a to B



When a resistor is applied with a voltage of 5V at both ends, the current passing through is 0.5A. If the voltage at both ends is increased by 15V, what is the resistance and the current passing through


This is simple. The value of the resistance can be calculated first. Remove the current of 0.5A with a voltage of 5V to get a resistance of 10 Ω. Remove the current of 10 Ω with a voltage of 15V to get a resistance of 1.5A