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If 50V voltage is applied at both ends of the resistance, and 20c electric quantity of the resistance passes through the cross section within 10 seconds, the resistance value of the resistance is______ Ω．
According to I = QT: the current I = 2010 = 2A; according to Ohm's Law: r = UI = 502 = 25 Ω; so the answer is: 25
If the electric quantity passing through a cross section of conductor is 5.2c in 10s, how many amperes? How many milliamperes?
Such as the title
1 Coulomb = 1 ampere x 1 second
10s, 5.2c, so the current is 0.52a = 520MA when the power per second is 5.2g10 = 0.52c
A: 520 ma
If the quantity of electricity passing through the cross-sectional area of a conductor is 5 banks and the work done by the current is 180J in 10s, the current passing through the conductor is 0
What is the voltage and resistance at both ends of the conductor
Electric quantity Q (Coulomb) = current I (ampere) * time t (second) 5 = I * 10 I = 0.5 A
Current work w (joule) = power P (watt) * time (second) 180 = u * 0.5 * 10 u = 36 V
Resistance R (Ohm) = voltage U (volt) / current I (ampere) r = 36 / 0.5 = 72 ohm
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