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When a voltage of 6V is applied at both ends of a conductor, the current passing through it is 0.4A, and the resistance of the conductor is__ If the voltage at both ends of the conductor becomes 9V, the resistance of the conductor is__ The current through the conductor is__ .
15 ohm, 15 ohm, 0.6 a
If the current through a resistor is 0.4A and the voltage on both sides is 6V, the resistance is () and if the voltage is doubled, the resistance is ()
The first empty, 6 / 0.4 = 15 Ω, fill in 15 Ω
Fill in the second blank
When the voltage at both ends of a resistor is 8V, the current passing through it is 0.4A. When the voltage is 6V, what is the resistance of the resistor? What is the current passing through it at this time? (regardless of the effect of temperature on resistance)
(1) The voltage of the resistor is 8V, the current is 0.4A, ∵ I = ur, ∵ resistance value of the resistor: r = UI = 8v0.4a = 20 Ω. (2) when the voltage at both ends of the resistor is changed, the material, length and cross-sectional area of the resistor remain unchanged, so the resistance value of the resistor remains unchanged. When the voltage of the resistor is 6V, I '= u ′ r = 6v20 Ω = 0.3A
A long straight wire with strong current is placed parallel above the cathode ray tube (left negative and right positive). The current direction is from right to left. As shown in the figure, the cathode ray will
A. Deflection into the paper
B. Deflection out of paper
C. Upward deflection
D. Downward deflection
First of all, the direction of the magnetic field of the cathode ray tube can be judged by the direction of the wire, which is perpendicular to the paper surface and outward, and then what to do?
In C CRT, electrons shoot from the negative pole to the positive pole, so the current is from the positive pole to the negative pole
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