The voltage at both ends of the conductor is 12 volts. The current passes through the conductor in 5 seconds and does 24 joules of work. During this period, the current passes through the cross section of the conductor

The voltage at both ends of the conductor is 12 volts. The current passes through the conductor in 5 seconds and does 24 joules of work. During this period, the current passes through the cross section of the conductor

Is that the charge passing through the cross section? Yes, that's the solution
w=Q*U
Where W is the energy, q is the total charge and u is the voltage
So q = 24J / 12V = 2 Coulomb

The voltage at both ends of a conductor is 6V, the current through the conductor is 0.5A, the amount of charge passing through the cross section of the conductor within 10s is () C, and the work of the current is () J

According to I = q / T, q = it = 5C current work w = uit = 30J energy-saving lamp 10h electric power 0.1kw? Incandescent lamp 10h Electric Power 1KW? So the energy-saving lamp saves 0.9k

When a wire passes through 0.5A current, the resistance is 10 Ω. Then when the voltage at both ends of the wire is 6V, what is the current and resistance through the wire

The current is 6V / 10 Ω = 0.6A
The resistance is 10 ohm

Physics (there is a question about whether two wires of different thickness are connected together and whether the currents in the two wires are equal under the same voltage)
Explain in physical language (not analogy)

Two wires of different thickness are connected together. Under the same voltage, the currents in two sections of wires are equal. They are regarded as two resistors of different sizes in series, and the currents in series circuit are equal everywhere