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When the voltage at both ends of a resistor increases from 3V to 4V, the current through it increases by 1a, and then the current in the conductor is? A
Let the current in the conductor be Xa, then
4/x=3/(x-1)
x=4
So the current in this conductor is 4a
For a certain resistance, the consumed electric energy is 16J when 2C charge is passed in 10s
When a certain resistance passes through the charge of 2C within 10s, the consumed electric energy is 16J
(1) What is the voltage across the resistor?
(2) If the electromotive force of the power supply of the circuit is 12V, what is the power consumption of the internal circuit of the power supply during this period?
(3) What is the power of the power supply?
It's best to translate the relationship of this series
1、I=q/t,I=0.2A;
W=UIt,U=8V
2. Total energy consumed by power supply e = EMF it = 24J
The external circuit consumes 16J
The internal circuit consumes 8j
3. P = e, EMF I = 2.4W
Marked with 12V 24 ohm and 3V 10 ohm resistors, if they are connected in series, the maximum voltage applied to both ends of the circuit is () V, and the total power consumption is () W
The current in the circuit should be the current with lower rated current among the two resistors, i.e. I = 0.3A. At this time, the voltage of one resistor is 3V and the voltage of the other resistor is 7.2V, so the maximum voltage in the circuit is 10.2v; the power consumed is p = I2 (R1 + R2) = 3.06w
When a 3V voltage is applied at both ends of a resistor, the current passing through it is 0.2A. If the current passing through it is increased by 0.1A, a () voltage should be applied at both ends of the resistor
Because my calculation is different from the answer,
R=U/I=15 U=RI=4.5v
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