When a resistance is increased by 3 Ω, the current in the circuit becomes four fifths of the original value. If the supply voltage remains unchanged, what is the original value of the resistance?

When a resistance is increased by 3 Ω, the current in the circuit becomes four fifths of the original value. If the supply voltage remains unchanged, what is the original value of the resistance?


twelve



What is the effect of resistance on current and voltage in series circuit?
I don't know the relationship between resistance voltage and current in series and parallel connection. It's very confusing. Give me some knowledge about this, let me straighten it out··


In series circuit, the current of each consumer is equal and the voltage is proportional to the resistance; in parallel circuit, the voltage of each consumer is equal and the current is inversely proportional to the resistance



If the resistance is 8 ohm and a planting resistance R is connected in series, and the voltage is inconvenient, if the resistance is increased to 10 ohm, what is the current variation range?


The resistance range of R is greater than 0 and less than 10 Ω
I0 = u / 8 (maximum current) at r = 0
I1 = u / 8 + 10 (minimum current) when r = 10
Then (i0-i1) / Io * 100% = 55.55555 %
The current change is not greater than 55.5555 of the current before increasing the resistance %



The resistance of a circuit is increased by 4 ohm, and the circuit becomes 2 / 3 of the original. If the voltage of the circuit remains unchanged, the later resistance in the circuit is (steps required)


Then the later resistance in the circuit is 8 + 4 = 12 ohm