How does the change of resistance of sliding rheostat affect the change of voltage This is the eighth edition of Zhejiang Education Press. May I ask why the voltage of sliding rheostat in the circuit (series or parallel) changes? Why does the resistance of constant value resistor not change but affect the voltage? Does sliding rheostat affect the current, resistance and voltage? Another question: which factors are related to the brightness of the bulb? Current, voltage or resistance? There must be a lot of additional points!

How does the change of resistance of sliding rheostat affect the change of voltage This is the eighth edition of Zhejiang Education Press. May I ask why the voltage of sliding rheostat in the circuit (series or parallel) changes? Why does the resistance of constant value resistor not change but affect the voltage? Does sliding rheostat affect the current, resistance and voltage? Another question: which factors are related to the brightness of the bulb? Current, voltage or resistance? There must be a lot of additional points!


In series and parallel circuits, the resistance of sliding rheostat changes
In a series circuit, the ratio of voltage is equal to the ratio of resistance
In parallel circuit, the ratio of current is equal to the inverse ratio of resistance
So in the circuit, when the resistance value of the sliding rheostat (connected to the circuit) changes, it causes the change of voltage or current. In the experiment, the resistance value of the constant value resistor (the characteristic of the constant value resistor) changes the voltage or current at its two ends
The change of resistance value of sliding rheostat will affect the voltage and current distribution of the whole circuit, but it is conditional
For example: in a series circuit, the resistance value of the sliding rheostat increases and the total resistance increases. Because the power supply voltage remains unchanged, the total current decreases. Because the voltage at both ends of the sliding rheostat and the constant value resistor is equal to the power supply voltage, and the ratio of the voltage at both ends of the sliding rheostat and the constant value resistor is proportional to the resistance, the voltage at both ends of the sliding rheostat increases and the voltage at both ends of the constant value resistor decreases
If it is in parallel circuit, the resistance value of sliding rheostat will increase, which will increase the total resistance. Because the power supply voltage remains unchanged, the main circuit current will decrease. In the branch circuit of sliding rheostat, because the voltage remains unchanged (still the power supply voltage), but the resistance will increase, so the current will decrease
Resistance is related to the composition of materials. Gold and silver have the lowest resistivity and can be used to conduct electricity. However, considering economic factors, the resistivity of copper is slightly higher than that of them, but most wires are made of copper wire. This is a property of objects. There are also some insulators with high resistance, some semiconductors and superconductors. In fact, these are all related to the properties of materials, The title says: "constant resistance" means: the resistance has not changed



Why does the voltage decrease with the increase of electric power in parallel circuit?
Daily home lighting circuit voltage is 220 V, often in the hot summer, due to large-scale air conditioning and other high-power electrical appliances, the voltage is often less than 220 v. so what is the specific reason for this phenomenon?


In real life, the voltage at both ends of electrical appliances is lower than 220 V, because there is a resistance on the transmission line. The resistance of wire is connected in series with electrical appliances to share part of the voltage. Electrical appliances are connected in parallel, and the more electrical appliances are used, the smaller the resistance is. More electrical appliances are used, the smaller the parallel resistance of electrical appliances is, and the voltage is shared by wire resistance in series, According to Ohm's law, when the voltage on the wire is high, the voltage of the appliance is low



In the circuit shown in the figure, the resistance R1 = 4 Ω, R2 = 6 Ω, and the resistance in the power supply R = 0.6 Ω. If the total power consumed by the power supply is 40W, and the output power of the power supply is 37.6w, calculate the electromotive force of the power supply and the resistance of the resistance R3


The power consumed by the internal resistance of the power supply is I2R = ptotal - ptotal: I = 2A & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; from ptotal = EI & nbsp; & nbsp; the total resistance of the external circuit is r = r1r2r1 + R2 + R3 & nbsp; & nbsp; from Ohm's law of closed circuit E = I (R + R) & nbsp