When a bulb is connected to a 220 V circuit, the power consumed is 40 W? (2) What is the resistance of the filament? (3) How much energy is consumed when working for 10 minutes?

When a bulb is connected to a 220 V circuit, the power consumed is 40 W? (2) What is the resistance of the filament? (3) How much energy is consumed when working for 10 minutes?


(1) From the deformation of P = UI, I = Pu = 40w220v = 0.18a answer: the current through the filament is 0.18a (2) from P = u2r, r = u2p = (220V) 240W = 1210 Ω answer: the resistance of the filament is 1210 Ω (3) w = Pt = 40W × 10min = 40 × 10 × 60s = 2.4 × 104j answer: working for 10min, the power consumption is 2.4 × 104



How much power does a 220 V, 700 w electric iron consume when it is plugged into a 110 V power supply? How to calculate?


First calculate the resistance of the electric iron
P = u ^ 2 / R, so r = u ^ 2 / P = 220 ^ 2 / 700 = 69.14 ohm
Actual power consumption P = u ^ 2 / r = 110 ^ 2 / 69.14 = 175W



A 220 V, 700 w electric iron, used in 110 V power supply, how much power it consumes? How to calculate, thank you


Power P = u ^ 2 / R
Now the input voltage is only half of the rated voltage
That's a quarter of the molecular square
The consumed power is one fourth of the rated power
So the answer is 175



How to calculate the power of a 220 v. 700 w electric iron when it is connected to 110 V power supply


220÷110=2
According to P = UI, 700 ÷ (2 × 2) = 175W