In {an}, A3 = 1 / 2, A9 = 8, then the value of A5 * A6 * A7 is A9/A3=(A1×q^8)/(A1×q^2)=q^6=8/(1/2)=16 q^3=±4 How to get Q ^ 3 = ± 4 in this non analytic expression? That is, Q ^ 6 = 16, how to delimit Q ^ 3 = ± 4?

In {an}, A3 = 1 / 2, A9 = 8, then the value of A5 * A6 * A7 is A9/A3=(A1×q^8)/(A1×q^2)=q^6=8/(1/2)=16 q^3=±4 How to get Q ^ 3 = ± 4 in this non analytic expression? That is, Q ^ 6 = 16, how to delimit Q ^ 3 = ± 4?


q^6=(q^3)^2=16
So Q ^ 3 = ± 4



In the equal ratio sequence {an}, A3 = 1 / 2, A9 = 8, find A5 × A6 × A7


a3*a9=a6^2=4
a5*a7=a6^2=4
a5*a6*a7=4a6
a^6=±2
a5*a6*a7=±8