A train loaded a batch of goods. Originally, 36 tons of energy-saving goods were loaded, but 80 tons were not loaded. Later, 4 tons more were loaded in each car, As a result, after loading the goods, there are just two carriages left. How many carriages does this train have? How many tons does this batch of goods have?

A train loaded a batch of goods. Originally, 36 tons of energy-saving goods were loaded, but 80 tons were not loaded. Later, 4 tons more were loaded in each car, As a result, after loading the goods, there are just two carriages left. How many carriages does this train have? How many tons does this batch of goods have?

Later, 36 + 4 = 40 tons per section
Wagon: (80 + 40 × 2) △ 4 = 40 knots
Cargo: 40 × 36 + 80 = 1520 tons

When a train loaded a batch of goods, it used to load 36 tons of energy-saving goods, but 80 tons were not loaded. Later, it broke through an extra 4 tons of each car, and it turned out that it was just right after the goods were loaded
There are two wagons left. How many wagons are there on this train? How many tons are there?

Suppose this train has x cars, according to "the original energy-saving loading 36 tons, the result is 80 tons not loaded", we can get the total cargo is: 36x + 80 tons. According to "later, each car broke through 4 tons, the result is that after loading the goods, there are exactly 2 cars left", we can get the total cargo is: 40 (X-2) tons

The freight train carries 90 tons of food in each carriage, and the remaining 60 tons can not be transported. If each carriage carries 110 tons, two carriages can be empty. How many carriages? How many tons of food are waiting to be transported
Urgent---

Answer:
There are x cars and Y tons of grain
According to the title, it can be concluded that:
90x + 60 = y (same grain quantity) 1
(X-2) X110 = y (same grain quantity) 2
Substituting 2 into 1
90X+60=(X-2)X110 3
Solution
X=14
Y=1320
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Each car of a can load 3 tons, each truck of B can load 2 tons, and the existing goods are 13 tons. How many cars do you need for each car?

X cars of a, y cars of B, XY are all positive integers
3x+2y=13
X = 1, y = 5 or x = 3, y = 2
A 1, b 5 or a 3, B 2