A kind of drink, the ratio of water and orange juice is 50:3. Now there are 12 grams of orange juice. How many kilograms do you need to add to make this kind of drink?

A kind of drink, the ratio of water and orange juice is 50:3. Now there are 12 grams of orange juice. How many kilograms do you need to add to make this kind of drink?

12÷3×50=200g=0.2kg

A bottle of orange juice drink 300 ml, in which the ratio of orange juice and water is 1:4, Xiaohong drink half, the rest of the drink, orange juice content is 20%______ ．

Because the content of orange juice = 11 + 4 × 100% = 20%, the answer is: √

Prepare 1000 ml of 20% sulfuric acid solution with a density of 1.14 GML. Several ml of concentrated sulfuric acid and water with a density of 1.84 kg / ml and a concentration of 98% are needed

126.44
nine hundred and seven point three five
The required mass of pure sulfuric acid is 20% * 1000 * 1.14 = 228g
The volume of concentrated sulfuric acid is (228 / 98%) / 1.84 = 126.44ml
The mass of concentrated sulfuric acid needed is 228 / 98% = 232.65g
The mass of sulfuric acid solution is 1000 * 1.14 = 1140G
The quality of water required is 1140-232.65 = 907.35
The volume of water required is 907.35ml