Inverted beverage bottle There is a drink bottle with a volume of 30 cubic decimeters. Now it contains some drinks. The height of the drink is 20 cm when it is placed upright, and the height of the rest part when it is placed upside down is 5 cm. The existing drinks in the bottle are () cubic decimeters The answer is 24 cubic decimeters, how to calculate? To calculate formula! Formula! Formula!

Inverted beverage bottle There is a drink bottle with a volume of 30 cubic decimeters. Now it contains some drinks. The height of the drink is 20 cm when it is placed upright, and the height of the rest part when it is placed upside down is 5 cm. The existing drinks in the bottle are () cubic decimeters The answer is 24 cubic decimeters, how to calculate? To calculate formula! Formula! Formula!


There is a drink bottle with a volume of 30 cubic decimeters. Now it contains some drinks. The height of the drink is 20 cm when it is placed upright and 5 cm when it is placed upside down. There are (24) cubic decimeters of drinks in the bottle
30×20/(20+5)=24



A mathematical problem of volume and volume
4. The glass container in the picture on the left has no cover, and the glass is 0.5cm thick. How many cubic centimeters of water can this glass container hold? How many milliliters?
Container length: 40cm
Width: 26cm
Height: 35.5cm


The inner wall of the vessel is 40-0.5 * 2 = 39cm in length, 26-0.5 * 2 = 25cm in width and 35.5-0.5 = 35cm in height
Volume = 39 * 25 * 35 = 34125 CC = 34125 ml



A mathematical problem about volume
The length and width are 6cm and 4cm rectangular iron sheets respectively, which form a cylindrical bucket with a bottom. What is the maximum volume of the bucket?


In this question, we should take the maximum area of the land, that is to say, take the height as 4
That is, 6 is the perimeter of the ground area
6=2πR R=3/π
S (bottom) = π R ^ 2 = 9 / π
V (volume) = 4 * (9 / π) = 36 / π



On volume and volume
If a rectangular glass fish tank with a length of 4 decimeters and a height of 4 decimeters is put into a rectangular iron block with a length of 2 decimeters, a width of 4 decimeters and a height of 2 decimeters, the following questions will be asked: (1) if the original water depth is 3. How many liters of water will overflow? (2) how many decimeters is the maximum water depth to keep the water from overflowing?


1. (4 * 5 * 3.5 + 2 * 4 * 2-4 * 5 * 4) / (4 * 5) = 0.3 decimeter
It will overflow 0.3 liters of water
2. (4 * 5 * 4-2 * 4 * 2) / (4 * 5) = 3.2 decimeters
In other words, the depth of water should be 3.2 decimeters at most?