The speed ratio of the passenger car to the freight car is 7:4. The two cars start from two places at the same time and run in opposite directions. They meet 18 km away from the midpoint. How many meters does the passenger car run?

The speed ratio of the passenger car to the freight car is 7:4. The two cars start from two places at the same time and run in opposite directions. They meet 18 km away from the midpoint. How many meters does the passenger car run?


With the same time, the passenger cargo distance ratio = passenger cargo speed ratio = 7:4
Total length = 18 × 2 ^ (7 / 11-4 / 11) = 36 ^ 3 / 11 = 132 (km)
At this time, the bus goes: 132 × 7 / 11 = 84 (km)
A: at this time, the bus traveled 84 kilometers



The speed ratio of the freight car to the passenger car is 3:4. The two cars leave from a at the same time. They have left each other and met 6 kilometers away from the destination. A
It requires a formula


The title is a mess. It should be the middle point
The speed ratio is 3:4, and the distance ratio is 3:4. There is one more share for the bus
If we meet at the midpoint of 6 km, the bus will run 6 * 2 = 12 km more, which is one share
Distance = 12 * (3 + 4) = 84 km



From a to B city, a travels 38 kilometers per hour and B 33 kilometers per hour. On the way, a stops for 3 o'clock and arrives 1 o'clock later than B. how far is the distance between a and B?
I want to
Detailed points of equation series


Let x do
Shea ran for X hours
38(x-3)=33(x-1)
5x=114-33
x=81/5
So the distance L = (81 / 5-1) * 33 = 15.2 * 33 = 501.6
Give points, I can hardly help people to solve math problems!



The two cars leave each other from a and B. car a travels 50 kilometers per hour and car B travels 60 kilometers per hour. After 4 o'clock, the distance is more than 20% of the whole journey
What's the formula


Whole course = (60 + 50) X4 / (1-20%) = 110x4 / 0.5 = 550km