Uncle Wang drove from place a to place B, traveling 70 kilometers per hour for 6 hours. 1. How far is it from place a to place B? 2 Uncle Wang drove from a to B, traveling 70 kilometers per hour for 6 hours How far is it from place a to place B? 2. Due to the task, the speed of returning was accelerated. It took only 4 hours to return to Jiadi. What was the speed of returning?

Uncle Wang drove from place a to place B, traveling 70 kilometers per hour for 6 hours. 1. How far is it from place a to place B? 2 Uncle Wang drove from a to B, traveling 70 kilometers per hour for 6 hours How far is it from place a to place B? 2. Due to the task, the speed of returning was accelerated. It took only 4 hours to return to Jiadi. What was the speed of returning?

1. 60 times 70

Uncle Wang drove 225km from place a to place B in the first three hours. According to this calculation, it took five hours from place a to place B. how far is the distance between two places?
To solve by proportion

Suppose the distance between a and B is x km, and the equation is formulated according to the meaning of the problem
x /（3+5） =225 / 3
3x=1800
x=600
A: the distance between a and B is 600 meters
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The distance between a and B is 270km. The local train leaves from a place at the speed of 50km per hour, and the express train leaves from B place at the speed of 60km per hour,
The slow train leaves for 1.5 hours first, and the two trains are facing each other. How long does it take for the slow train to leave before they meet?

Let the slow train run for X hours, and the two trains meet; when they meet, the slow train runs for 50x kilometers, the fast train runs for (x-1.5) hours, and the fast train runs for 60 (x-1.5) kilometers
50x+60(x-1.5)=270
50x+60x-90=270
50x+60x=270+90
110x=360
x=36/11
The formula is as follows
1.5+(270-1.5×50)÷(50+60)
=1.5+(270-75)÷110
=1.5+195÷110
=1.5+39/22
=3/2+39/22
=33/22+39/22
=36 / 11 hours
A: 36 / 11 hours after the local train leaves, the two cars meet

The distance between Party A and Party B is 270km. The local train starts from place a at the speed of 50km per hour, the express train starts from place B at the speed of 60km per hour, and the local train starts at 1
When the local train leaves for X hours, the two trains will meet. The equation is

50+（50+60）x=270
The solution is x = 2
A: two hours after the local train leaves, they meet