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Party A and Party B meet for the first time eight minutes after they set out on the 400 meter circular runway with a point a facing away. It is known that Party A travels 0.1 meters more per second than Party B, So, what is the shortest distance between the place where they meet for the fifth time and point a along the runway?
A runs 6 meters more per minute than B, so he runs 48 meters more in 8 minutes,
Because they met five times, they ran a total of 400x5 = 2000 meters
So B ran (2000-48) / 2 = 976m
So the shortest distance is 976-400x2 = 176m
A and B are on the 400 meter long circular runway. A travels 1 meter more per second than B. if it takes 25 seconds for two people to meet for the first time, calculate the speed of the second person
Let the velocity of B be x respectively, then the velocity of a be x + I, and the equation is given
(x+1)*t+x*t=400
The solution is x = 7.5
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