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The two trains leave from a and B at the same time. After 4 hours, they meet at 48km from the midpoint. B knows that the speed of the local train is 7 / 5 of that of the express train The two trains leave from a and B at the same time and meet at 48km from the midpoint after 4 hours. It is known that the local train is 5 / 7 of the speed of the express train. What are the speeds of the express train and the local train? How many kilometers are there between a and B?
1. 48 × 2 ÷ 4 = 24 km / h, the fast train takes more distance per hour than the slow train
2. 24 ÷ (7 / 5-1) = 60 km. H, idle speed
3. 60 ÷ (5 / 7) = 84 km / h, fast speed
4. (60 + 84) × 4 = 576km, distance between a and B
The two trains leave each other from a and B and meet at 72km from the midpoint three hours later. It is known that the speed of the local train is 5 / 7 of that of the express train. How many kilometers are there between a and B?
If the speed of the slow train is set at 5x km / h, the speed of the fast train is set at 7x km / h,
The equation is: 3 * (7x-5x) = 72
x=12
So, we have to: the local speed is 60 km / h, and the fast speed is 84 km / h,
The total distance is: (60 + 84) * 3 = 432 (km)
It is known that the speed ratio of the fast train to the local train is 5:3. The two trains run from station a and B at the same time, and meet at 75 km away from the midpoint station. After meeting, the two trains continue to run
When the express arrives at station B, how many kilometers is the local train from station a?
Whole course: 75 × 2 △ 5-3 × (5 + 3) = 600 km
When the express arrives at station B, the distance between the local train and station a is 600 × (1-3 / 5) = 240 km
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