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The fast and slow trains start from a and B at the same time and run in opposite directions. After 3.5 hours, they meet at a distance of 3.5 kilometers from the midpoint?
sususuyuanyuan
When meeting, it is 3.5km away from the midpoint, that is, when meeting, the distance of fast train is more than that of slow train: 3.5 × 2 = 7 (km)
The speed difference between express train and local train: 7 / 3.5 = 2 (km)
So slow train per hour: 70-2 = 68 (km)
A: the local train runs 68 kilometers per hour
The two cars leave each other from a and B, and meet at 48km from the midpoint after 4 hours. It is known that the speed of the slow train is 3 / 5 of that of the fast train. How many thousand kilometers are there between a and B
If the fast train speed is x, the slow train speed is 3 / 5x, and the distance between a and B is y, the following two equations can be obtained:
①Y=4×（1+3/5）X；
②Y/2+48=4X；
Solve the equations
X = 60
Y=384
It is known that the speed of the local train is 5 / 6 of that of the express train. The two trains are going towards each other from station a and B at the same time, and they meet at 4km away from the midpoint. What is the distance between station a and B?
I can't figure it out without time
When we meet,
The slow train is also 5 / 6 of the fast train
The local train runs 4 × 2 = 8 km less than the express train
The express train runs 8 (1-5 / 6) = 48 km
The local train runs 48-8 = 40 km
Distance between Party A and Party B: 48 + 40 = 88 km
The speed of the local train is 57 times that of the express train. The two trains leave from station a and station B at the same time and run in opposite directions. They meet 36 kilometers away from the midpoint. How many kilometers did the express train travel when they meet?
(36 × 2) / (7-5) × 7, = 72 × 2 × 7, = 252 (km); a: the express drove 252 km when it met
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