On the map with a scale of 1:4000000, the distance between a and B is 30cm. When will the two vehicles meet each other?

On the map with a scale of 1:4000000, the distance between a and B is 30cm. When will the two vehicles meet each other?


4000000 × 30 = 120000000 (CM) = 1200 (km)
Let two cars meet in X hours
70x+50x=1200
120x=1200
x=10
A: the two cars will meet in 10 hours
(the man above said 100000 is 1 km = 100000 cm)



On a map with a scale of 1:4000000, the distance between the two places is 35cm,


1:4000000=35:x
x=35*4000000
1:35000000=y:35*4000000
Ψ y = 4 (CM)
If the distance between the two places is drawn on a map with a scale of 1:35 million, it should be 4 cm



On the map with a scale of 1:6000000, the distance between a and B is 8 cm, and a car drives from a to B at a speed of 80 kilometers per hour
It will arrive in a few hours


Distance = 8 × 6000000 = 48000000cm = 480km
Arrival = 480 △ 80 = 6 hours



On the map with a scale of 1:3000000, it is measured that the distance between a and B is 3.6cm. How many hours can a car arrive from a tunnel B at a speed of 60km per hour?


3.6 △ 13000000, = 3.6 × 3000000, = 10800000 (CM), 10800000 cm = 108km, 108 △ 60 = 1.8 (H); a: it can be reached in 1.8 hours