After a substance is fully burned in oxygen, it will produce carbon dioxide and water. The substance must contain carbon and hydrogen. It may contain oxygen. Why

After a substance is fully burned in oxygen, it will produce carbon dioxide and water. The substance must contain carbon and hydrogen. It may contain oxygen. Why


The type of elements before and after the chemical reaction is the same. The products are carbon dioxide and water. Therefore, the products contain three elements: carbon, hydrogen and oxygen. Therefore, the reactants must also contain these three elements. Because oxygen only contains oxygen, the material must contain hydrocarbon, possibly oxygen



Take 2.16 g of the material and make it burn fully. It is measured that only 2.16 g of hydrated carbon dioxide and 5.28 g of carbon dioxide are produced. How much hydrogen and carbon are contained in the material
According to the mass conservation, before reaction = after reaction, why take 2.16 g of this material to generate 2.16 g of hydrated 5.28 g of carbon dioxide?


(because oxygen is involved in the reaction)
Hydrogen element: 2.16G * 2 / 18 = 0.24g
Carbon element: 5.28g * 12 / 44 = 1.44g



The amount of money for Party A and Party B is 3:1. If Party A gives Party B 0.5 yuan, the ratio of money for Party A and Party B is 2:1. What is the amount of money shared by Party A and Party B


Let a have 3x yuan and B have X Yuan
3X-0.5=2(x+0.5)
X=1.5
4 * 1.5 = 6 yuan



A and B two cars from AB two places at the same time, a car travel 60 kilometers per hour, B car travel 45 kilometers per hour, two cars at the same time
How many kilometers is the distance between AB and ab?


30÷【1/2-45/(45+60)】
=30÷【1/2-3/7】
=30÷1/14
=420 km



A and B start from two places at the same time. A runs 58 kilometers per hour, B 48 kilometers per hour, and then they meet each other 20 kilometers from the midpoint


Arithmetic
(58 + 48) × [20 × 2 ÷ (58-48)] = 424km
Lie equation
Suppose two cars meet in X hours. After meeting, a travels 20 × 2 kilometers more than B
58X=48X+20×2
The solution is x = 4 (hours)
The distance between the two places is
(58 + 48) × 4 = 424km