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There are two engineering teams. The first team has 146 people and the second pair has 88 people. How many people can be transferred from the first pair to the second pair to make the number of the two teams equal? Please ask God for help
Suppose x people are transferred from the first team to the second team to make the two teams equal. 146 -- X = 88 + X 2x = 58, x = 29
Two teams do exercises and transfer one fifth of the number of the first team to the second team. The number of the two teams is equal. What is the ratio of the first team to the second team?
The ratio of the first and second teams is 1: (1-1 / 5 × 2) = 5:3
The children lined up in two teams. Mr. Wang transferred three children from the first team to the second team. The number of the two teams was just the same. It turned out that the first team was more than the second team
A kid?
If the first team has X members and the second team has y members, then
X-3 = y + 3, that is, X-Y = 6
So six more
Divide 100 people into four teams. The number of the first team is 4 / 3 times that of the second team and 5 / 4 times that of the third team. How many people are there in the fourth team?
List the equation, once a dollar equation. I haven't learned anything else, but once a dollar. Don't make it so difficult!
There are X members in the first team and y members in the fourth team
X+3/4X+4/5X+Y=100
Let's solve this Diophantine equation,
10. Y is a positive integer, so x is a common multiple of 4,5. Here we can only take 20,
So the fourth team has 100-20-15-16 = 49
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- 1. The number of the first team is 38 less than twice that of the second team. 10 people are transferred from the first team to the second team, and half of the original number of the second team is transferred to the first team The number of first and second teams I've made an equation, but there's something wrong with it
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