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The railway between station a and station B is 960 km long. A passenger train runs from station a to station B, and a train runs from station B to station a. the passenger train runs every hour 110 kilometers, 90 kilometers per hour, after a few hours, 20% meet?
960 / (110 + 90) = 4.8 hours
After 4.8 hours, the two cars met
The railway between station a and station B is 660 km long. At 10:30 a.m., a train runs from station a to station B at the speed of 90 km / h, and a freight car runs from station B to station a at the speed of 75 km / h. then when do the two trains meet in the afternoon?
660 △ 90 + 75 = 660 △ 165 = 4 (hours); 10:30 + 4 hours = 14:30, that is 2:30 p.m
Car a and car B leave from a and B which are 420 kilometers apart at the same time. Five hours later, car a runs 34 times and car B runs 23 times. How many kilometers are there at this time?
420 × (34 + 23-1), = 420 × (1712-1), = 420 × 512, = 175 (km); a: the distance between the two cars is 175 km
Car a and car B leave from a and B which are 420 kilometers apart at the same time. Five hours later, car a runs 34 times and car B runs 23 times. How many kilometers are there at this time?
420 × (34 + 23-1), = 420 × (1712-1), = 420 × 512, = 175 (km); a: the distance between the two cars is 175 km
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